Learning objectives
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Outcome
State the two postulates of special relativity and name the classical assumption that each one rejects.
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Outcome
Compute a speed with and compare the result with the Galilean value for given and .
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Outcome
Use the relative error of Galilean addition to determine for which classical mechanics stays within 1 % error and for which it becomes inapplicable.
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Outcome
Explain, using the spectrum of a moving source, why the constancy of contradicts Galilean velocity addition.
Understand the idea
Einstein's Postulates and the Limits of Classical Mechanics
Text
Classical mechanics rests on two tacit assumptions: time is absolute () and velocities add simply, (Galilean relativity). Maxwell's electromagnetism, however, predicts waves travelling in vacuum at , a speed fixed by constants of nature rather than by the motion of the source; the emission spectrum shows that a moving source shifts the frequency (the lines move) but does not change the propagation speed. Einstein removed the conflict with two postulates: (1) the principle of relativity — all inertial frames are equivalent for every law of physics, not only for mechanics; (2) the constancy of the speed of light — every inertial observer measures the same vacuum value , regardless of the motion of source or observer. Together these postulates demand the Lorentz transformation instead of the Galilean one, and hence time dilation, length contraction, and relativistic velocity addition . Classical mechanics is not wrong: it is the low-speed limit , where and the Galilean formula is recovered. The limits appear wherever speeds approach : fast particles, precise time synchronisation (GPS), and the propagation of light itself.
Worked examples
Direct
Problem
A spacecraft recedes from Earth at and launches a probe forward at relative to the spacecraft. Find the probe's speed relative to Earth with the relativistic formula and compare it with the Galilean answer.
Solution
Both velocities lie along the same line, so we use the velocity-addition formula:
The Galilean count would give
The relativistic result is below , whereas the Galilean one already reaches the limit ; at any higher speeds it would give , which is impossible for a massive probe. This is a direct consequence of the second postulate: no addition of velocities can exceed .
Application
Problem
Two stages accelerate a craft: relative to Earth a stage moves at , and a module separates from it at in the same direction. Find the module's speed relative to Earth and the relative error that classical mechanics would give. May Galilean addition be used in this problem?
Solution
Relativistic calculation.
Galilean calculation: .
Relative error:
An error of 12 % vastly exceeds the acceptable 1 % threshold, so Galilean addition may not be used here. Note that for equal speeds the error is approximately , so the 1 % threshold requires .
Transfer
Problem
A star recedes from an observer at and emits light that reaches the observer. In the star's frame the light travels toward the observer at . What does Galilean addition predict, and what does the relativistic formula give? Is the answer consistent with the spectrum: the star's spectral lines are shifted to longer wavelengths by about a factor 1.36 in wavelength?
Solution
Galilean prediction:
That is, the observer would see light travelling at — and the "speed of light" would depend on the motion of the source.
Relativistic calculation:
The speed magnitude equals for any : substituting into the formula always gives . This is exactly what the second postulate asserts.
Consistency with the spectrum. The red shift of the lines ( with gives , i.e. a wavelength stretch of about 1.36) reveals the motion of the source but not a slowing of light: the frequency changes while the propagation speed stays . Hence the classical rule cannot be applied to light and must be replaced by the relativistic one.
Practice
Text
- Open an available interactive special-relativity simulation (a light clock or a relativistic velocity adder), or a spreadsheet.
- Build a table: with fixed and from to in steps of , compute
- Plot against ; mark the point where and the point where . Check that as the value , while (it grows linearly with and exceeds for ).
- State a conclusion: up to which the classical formula keeps the error below 1 %, and why it cannot be used for light.
Safety. A numerical experiment and a simulation are sufficient. Do not run experiments with radiation sources, high-voltage vacuum tubes, or fast particles.
Visual reference
Purpose
Show where Galilean velocity addition violates the second postulate and how the relativistic formula keeps every speed below the limit .
Representation
A graph: horizontal axis over the range to , vertical axis for fixed . Two curves — the straight line (rising above the level for ) and the curve , which reaches at (and at ) and stays within the light-speed limit. Mark the example points: gives , while gives for any .
Real-world examples
GPS satellite clocks
Scenario
A GPS satellite orbits at an altitude of 20 200 km with a speed of about relative to the ground. Its radio signal covers the to your phone in , and the receiver turns that travel time into a distance to within a few metres.
Connection
The second postulate is at work here: in the receiver's frame the signal travels at exactly , whatever the satellite's motion. The Galilean rule would shift the range by — far more than the few metres the travel-time measurement actually delivers.
Headlight and horn: where velocity addition breaks
Scenario
A train moves at (108 km/h) towards a horn sounding in still air. A passenger measures the sound arriving at — the ordinary Galilean sum, an change. The same passenger then measures the light from a lamp: classical addition would give , a shift of only of , too small to see. The decisive test used the Earth's orbital motion, , that is , which a Michelson interferometer could resolve — and no change in the speed of light was found.
Connection
Classical mechanics is built on adding velocities, and for sound the rule holds: the passenger's is exactly what Galilean relativity predicts. The second postulate says light does not obey it: a lamp and a star give the same for every inertial observer, so no frame exists in which light is at rest — and with that frame the classical picture of an absolute space in which light propagates loses its footing.
Muons that should not reach the ground
Scenario
Cosmic rays create muons about above the ground. A muon flies at and has a mean lifetime of . Classical kinematics gives a mean path of , so only a fraction should survive the trip. In fact about one muon crosses each square centimetre of ground every minute.
Connection
This is the limit of classical mechanics in a single measurement. Under Galilean transformations neither the lifetime nor the of air changes between frames, so classical kinematics has no way to account for the observed flux; 'time' and 'length' themselves must depend on the frame, and the postulates are the minimal assumptions that deliver that dependence.