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crystalline amorphous and anisotropic solids

Learning objectives

  • Outcome

    From a T(t)T(t) graph and a diffraction pattern, decide whether a given body is crystalline or amorphous and write the justification in one or two sentences.

  • Outcome

    Name at least two properties of a single crystal that depend on direction and state the crystallographic directions along which they were measured.

  • Outcome

    Calculate the number of particles per unit cell (SC, BCC, FCC) and the density of a crystal from the lattice parameter aa and the molar mass MM.

  • Outcome

    Explain why an amorphous body and a fine-grained polycrystal behave as isotropic, using averaging over particle or grain orientations.

Understand the idea

Crystalline, Amorphous and Anisotropic Solids

Text

A solid keeps its shape and volume, and the difference between crystalline and amorphous bodies is set by how their particles are arranged relative to one another. In a crystal the particles (atoms, ions, molecules) form long-range order: a repeating motif — the unit cell — is reproduced over distances far larger than the interatomic spacing, so melting occurs at a sharply defined temperature TfT_f and the T(t)T(t) graph shows a horizontal plateau. An amorphous body has only short-range order, as a liquid does: on heating it softens gradually over a range of temperatures. Anisotropy is the dependence of physical properties (thermal conductivity λ\lambda, refractive index nn, Young's modulus EE, expansion coefficient α\alpha) on direction inside the body. In a single crystal anisotropy follows directly from the ordered lattice: interparticle spacings and bond types differ along different crystallographic directions. An amorphous body has no preferred directions and is therefore isotropic; a polycrystal also behaves as an isotropic body while its grains are small compared with the sample, because grain orientations average out.

Worked examples

Direct

Problem

A sample of a solid is heated slowly. Its temperature-versus-time graph shows a horizontal plateau at 273 K273\ \text{K}, and X-ray diffraction gives a set of sharp narrow peaks. Is this body crystalline or amorphous? Justify your answer.

Solution
  1. Sharp narrow diffraction peaks mean that scattering occurs on periodically spaced planes, that is, the body has long-range order — a repeating unit cell.
  2. The horizontal plateau on the T(t)T(t) graph means that all supplied heat goes into breaking the lattice at one temperature, that is, melting occurs at a definite TfT_f.
    Conclusion: the body is crystalline. An amorphous body would give broad diffuse halos instead of peaks and would soften gradually, with no plateau.

Application

Problem

Find the density ρ\rho of a copper single crystal with an FCC lattice if the lattice parameter is a=3,61×10−10 ma = 3{,}61\times10^{-10}\ \text{m}, the molar mass is M=63,55 g/molM = 63{,}55\ \text{g/mol} and Avogadro's constant is NA=6,02×1023 mol−1N_A = 6{,}02\times10^{23}\ \text{mol}^{-1}.

Solution
  1. Particles of an FCC cell: 8 corners contributing 1/81/8 each and 6 face centres contributing 1/21/2 each:

n=8⋅18+6⋅12=4.n = 8\cdot\frac{1}{8} + 6\cdot\frac{1}{2} = 4.

  1. Cell volume: V=a3=(3,61×10−10)3=4,70×10−29 m3V = a^3 = (3{,}61\times10^{-10})^3 = 4{,}70\times10^{-29}\ \text{m}^3.
  2. Density follows from the mass of particles in the cell:

ρ=nMNAa3=4⋅63,55×10−36,02×1023⋅4,70×10−29=0,25422,83×10−5≈8,98×103 kg/m3.\rho = \frac{nM}{N_A a^3} = \frac{4\cdot63{,}55\times10^{-3}}{6{,}02\times10^{23}\cdot4{,}70\times10^{-29}} = \frac{0{,}2542}{2{,}83\times10^{-5}} \approx 8{,}98\times10^{3}\ \text{kg/m}^3.

The result is close to the tabulated density of copper 8,96×103 kg/m38{,}96\times10^{3}\ \text{kg/m}^3, which supports the FCC model.

Transfer

Problem

Graphite has a layered structure: inside a layer the atoms are joined by strong covalent bonds, while weak van der Waals forces act between the layers. The thermal conductivity along the layers is λ∥≈400 W/(m⋅K)\lambda_{\parallel} \approx 400\ \text{W/(m}\cdot\text{K)} and across the layers λ⊥≈4 W/(m⋅K)\lambda_{\perp} \approx 4\ \text{W/(m}\cdot\text{K)}. Explain the origin of the anisotropy, estimate the ratio λ∥/λ⊥\lambda_{\parallel}/\lambda_{\perp} and predict whether a pressed graphite powder will be anisotropic. Justify your answer.

Solution
  1. Along a layer the bonds are strong and stiff, so lattice vibrations pass easily and delocalized electrons add an extra channel for heat; across the layers the bonds are weak, few heat paths exist and the resistance is high. Hence the anisotropy: the property depends on direction because spacings and bond types differ along different directions.
  2. Ratio: λ∥λ⊥=4004=100.\frac{\lambda_{\parallel}}{\lambda_{\perp}} = \frac{400}{4} = 100.
  3. Pressed powder is a polycrystal: the grains are randomly oriented, and along any heat path the layers are met at all possible angles. The measured quantity is an average over orientations, so macroscopically the powder is isotropic. If pressing produces a texture (a preferred orientation of the layers), anisotropy returns: along the stacking plane λ\lambda will be noticeably larger than across it.

Practice

Text

Work with models only, without heating and without hazardous substances.

  1. Open a browser-based crystal-lattice simulation or a molecular-dynamics visualisation of a solid. Build SC, BCC and FCC cells, record the number of particles per cell (11, 22, 44) and compute the packing fraction

k=n⋅43πr3a3,k = \frac{n \cdot \frac{4}{3}\pi r^3}{a^3},

assuming the particles touch one another. Compare your result with the known values 0,520{,}52, 0,680{,}68, 0,740{,}74.
2. In a birefringence simulation, place a calcite crystal in the beam path and rotate it slowly, noting whether the beam splits into two. Then replace the calcite with isotropic glass and repeat.
3. In a molecular-dynamics model of an amorphous body, raise the temperature and record how particle mobility changes: does a sharp jump appear at one temperature, or a gradual softening?
4. Write the summary as three lines: type of body — observed feature — explanation in terms of particle arrangement.

Visual reference

Purpose

Show the link between particle arrangement, melting behaviour and the direction dependence of properties, so that one figure explains the crystal, the amorphous body and anisotropy at once.

Representation

Three parts on one sheet.

(a) Particle-arrangement sketch: on the left, a flat single-crystal lattice with the unit cell outlined by a dashed contour; on the right, a chaotic cluster of particles of an amorphous body with short-range order.

(b) T(t)T(t) graphs: for the crystal, a rising slope, a horizontal plateau at TfT_f, then a rise again; for the amorphous body, a smooth softening curve with no plateau.

(c) Polar diagram of a property (for example λ\lambda or EE): for the single crystal, a closed curve elongated along the direction of strong bonding; for the amorphous body, a circle showing the same value of the property in all directions.

Real-world examples

Anisotropy of a carbon-fibre bicycle frame

Scenario

A racing frame of mass 1,1 kg1{,}1\,\mathrm{kg} carries a cyclist of mass 70 kg70\,\mathrm{kg}; in a sprint the rider produces 500 W500\,\mathrm{W} and travels at 45 km/h45\,\mathrm{km/h}. Carbon fibres are laid along the frame tubes: the elastic modulus along a fibre is about 230 GPa230\,\mathrm{GPa}, while across it is about 15 GPa15\,\mathrm{GPa}.

Connection

This exercises anisotropy: the elastic properties of crystalline graphite and of the fibre depend on direction. In a graphite layer strong covalent bonds act in the basal plane, while weak van der Waals forces act between planes; therefore stiffness along the tube and across it are unequal, which is described by the elasticity tensor of an anisotropic solid.

Amorphous screen glass and crystalline sapphire in a smartphone

Scenario

A smartphone screen is a layer of amorphous glass 0,7 mm0{,}7\,\mathrm{mm} thick; the camera cover is crystalline sapphire 0,3 mm0{,}3\,\mathrm{mm} thick. Glass hardness is 66–77 on the Mohs scale, sapphire hardness is 99; in a fall from 1,5 m1{,}5\,\mathrm{m}, glass more often gets scratches, while sapphire chips along certain planes.

Connection

Here the distinction between amorphous and crystalline states is at work: glass has no long-range order, so its hardness and refractive index are the same in all directions; sapphire has a periodic lattice, and its hardness, thermal conductivity and refractive index are anisotropic, while cleavage runs along crystallographic planes.

Tempering chocolate: crystalline and amorphous phases of cocoa butter

Scenario

A chocolate bar of mass 100 g100\,\mathrm{g} is heated to 45 ∘C45\,^{\circ}\mathrm{C}, then cooled to 27 ∘C27\,^{\circ}\mathrm{C} and warmed again to 31 ∘C31\,^{\circ}\mathrm{C}. The stable crystalline form V of cocoa butter melts at 34 ∘C34\,^{\circ}\mathrm{C}, while rapidly cooled amorphous and unstable forms melt at 2323–28 ∘C28\,^{\circ}\mathrm{C}; at room temperature 20 ∘C20\,^{\circ}\mathrm{C} a tempered bar snaps firmly, while an untempered one is soft and dull.

Connection

The example shows crystalline and amorphous states of one substance: crystalline form V has long-range order and a sharp melting point at 34 ∘C34\,^{\circ}\mathrm{C}, whereas the amorphous/glassy phase has no long-range order and melts/softens over a broad interval. Different crystalline polymorphs are different lattices made of the same molecules, which changes strength and gloss.